Shaun said:math
500 CFM = 14.16 m^3 / min = approx 14kg/min = approx 233g/s
3.0L at 6500 redline and 100% VE (generously) = 380CFM = approx 177g/s
both assuming air is around 90 F
jawzsg said:Well hullo, this thread is pretty interesting as well as technical. I'm pretty layman and have figure out the followings;
A 2.2L engine on 4 strokes = 2200cc /4 = 550cc of air/stroke (i.e. induction stroke). At 6500 rpm, the induction would have been 6500 x 550cc of air = 3,575,000cc = 3,575L of air.
3,575L = 3.575 x 36 = about 130 cu. ft. That is alot of air the engine consumes in a minute. Wow. Err.. how much air does the bilge blower move in a minute? My 2 cents worth.![]()