yendor
Well-Known Member
Ok let me start the ball rolling by placing this hypothesis on the table.
A lower spark ionisation voltage allows the spark plug a larger aperture for the spark to jump across and the resultant spark is more intense due the larger amount of energy available to perform ionisation.
This has the effect of advancing ignition by fractions of a degree and up to a degree max at max RPM. In addition to this small benefit, a low ionisation voltage intense spark gives "accurate" burn timings.
The definition of "accurate" is what i define in the following steps
1. ECU generates command to ignite based on values of its map. (assume as reference in this case)
2. ECU output transistors amplify signal to generate a square pulse. ( slew rates of analog amplifiers apply)
3. Signal propagates along wires to the ignition amplifiers. ( propagation along wires taken as negligible as it is constant for all systems)
4. Ignition amplifiers act on the pulses and on the positive edge to commence charging of coil and on the negative slope cut off the current and the coil generates the spark. ( slew rates of amplifiers apply, Output of the coil is proportional to the rate of decrease of the current. V = L x dI/dT. In english is the output voltage is equal to the inductance of the coil multiplied by the rate of current change. The result of this is a voltage that increases with time and requires a finite time to reach maximum voltage)
5. The energy travels along HT cables or conductors. (propagation also is a constant. Distributor systems are not included)
6. Energy builds up across the tips of the spark plug and any voltage above the instaneous ionisation voltage results in a spark whereby the energy of the coil that is greater than the ionisation level goes into the intensity of the spark.
To be "accurate" I want the shortest possible time lag and the strongest spark to fire all kinds of mixtures.
In terms of mixtures, I will go so far as to say that the mixture in the entire combustion chamber is not homogenous and that there are leaner areas and richer areas. This will change the dielectric (insulating) properties of the spark gap and thus raising or lowering the ionisation voltage. Lean mixtures have higher dielectric value and thus higher voltage required to allow sparking and converse for richer mixtures.
If we hold the gap and construction of plug constant, the ionisaton voltage will only depend on the instaneous insulating properties of the mixture. If you narrow the gap, the flame front is smaller and cyl pressures are not fully optimised. If the gap is increased, spark area is large but intensity is weaker, also sub-optimal operation.
To raise the ionisation voltage of materials, they are made round and free of points. This will spread the electrical charge over the entire area. ( witness the insulators of HT electrical transmission lines and you will see nice curvy ceramic insulators. The static electricity generator has a sphere on the top for the same reason.)
Thus using this property, spark plug manufacturers produce smaller tips to reduce the ionisation voltage. The challenge all along was to find a material that can withstand the intense heat of sparking ( not combustion temp) without evaporation or transfer of electrode material and the welding of such metals. Of course must be done at cheap commercial rates. The whole exercise is to produce sharp points. (iridium/platinium electrodes, ND U grove, Split Fire V grove...)
So a lower ionisation voltage allows the spark to happen earlier and fire through a greater range of mixtures moving around the chamber with greater intensity.
I have deliberately removed all traces of values to limit this to a discussion on concepts.
Quantitative values may come later when dyno figurers come.
Lets discuss about this concept.
Opinions?
Cheers
Rodney
A lower spark ionisation voltage allows the spark plug a larger aperture for the spark to jump across and the resultant spark is more intense due the larger amount of energy available to perform ionisation.
This has the effect of advancing ignition by fractions of a degree and up to a degree max at max RPM. In addition to this small benefit, a low ionisation voltage intense spark gives "accurate" burn timings.
The definition of "accurate" is what i define in the following steps
1. ECU generates command to ignite based on values of its map. (assume as reference in this case)
2. ECU output transistors amplify signal to generate a square pulse. ( slew rates of analog amplifiers apply)
3. Signal propagates along wires to the ignition amplifiers. ( propagation along wires taken as negligible as it is constant for all systems)
4. Ignition amplifiers act on the pulses and on the positive edge to commence charging of coil and on the negative slope cut off the current and the coil generates the spark. ( slew rates of amplifiers apply, Output of the coil is proportional to the rate of decrease of the current. V = L x dI/dT. In english is the output voltage is equal to the inductance of the coil multiplied by the rate of current change. The result of this is a voltage that increases with time and requires a finite time to reach maximum voltage)
5. The energy travels along HT cables or conductors. (propagation also is a constant. Distributor systems are not included)
6. Energy builds up across the tips of the spark plug and any voltage above the instaneous ionisation voltage results in a spark whereby the energy of the coil that is greater than the ionisation level goes into the intensity of the spark.
To be "accurate" I want the shortest possible time lag and the strongest spark to fire all kinds of mixtures.
In terms of mixtures, I will go so far as to say that the mixture in the entire combustion chamber is not homogenous and that there are leaner areas and richer areas. This will change the dielectric (insulating) properties of the spark gap and thus raising or lowering the ionisation voltage. Lean mixtures have higher dielectric value and thus higher voltage required to allow sparking and converse for richer mixtures.
If we hold the gap and construction of plug constant, the ionisaton voltage will only depend on the instaneous insulating properties of the mixture. If you narrow the gap, the flame front is smaller and cyl pressures are not fully optimised. If the gap is increased, spark area is large but intensity is weaker, also sub-optimal operation.
To raise the ionisation voltage of materials, they are made round and free of points. This will spread the electrical charge over the entire area. ( witness the insulators of HT electrical transmission lines and you will see nice curvy ceramic insulators. The static electricity generator has a sphere on the top for the same reason.)
Thus using this property, spark plug manufacturers produce smaller tips to reduce the ionisation voltage. The challenge all along was to find a material that can withstand the intense heat of sparking ( not combustion temp) without evaporation or transfer of electrode material and the welding of such metals. Of course must be done at cheap commercial rates. The whole exercise is to produce sharp points. (iridium/platinium electrodes, ND U grove, Split Fire V grove...)
So a lower ionisation voltage allows the spark to happen earlier and fire through a greater range of mixtures moving around the chamber with greater intensity.
I have deliberately removed all traces of values to limit this to a discussion on concepts.
Quantitative values may come later when dyno figurers come.
Lets discuss about this concept.
Opinions?
Cheers
Rodney