Question for the Forumers
- Thread starter kenntona
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wobbles
Well-Known Member
Re: Question for the Forumers
Divvy up into 3 piles of 4 cars. We'll call this pile A, pile B & pile C. Weigh any of the 2 piles on the balancing scale.
Scenario (a) - if A & B balances, then the fake M3 must be in pile C. Divide Pile C (4 cars) into 2 cars each. Let's say 3 of the real Ms are represented by RED and the lone fake M is represented by BLUE.
So, now you weigh ONE car against another from Pile C. If the first weighing balances, that means the FAKE M is in the last pile. So, all you need is to take ANY car from the final pile, and weigh this against ANY car from ANY of the other piles. If this final weighing balances, the FAKE M is the last car. If it doesn't balance, then, you know you've placed the FAKE M on weighing scale, because you're comparing that to ANY of the other cars (which are REAL Ms)
Scenario (a) means minimum 3 weighings.
The rest of the scenarios are just permutations of the 1st, and they all work out to THREE minimum weighings.
Divvy up into 3 piles of 4 cars. We'll call this pile A, pile B & pile C. Weigh any of the 2 piles on the balancing scale.
Scenario (a) - if A & B balances, then the fake M3 must be in pile C. Divide Pile C (4 cars) into 2 cars each. Let's say 3 of the real Ms are represented by RED and the lone fake M is represented by BLUE.
So, now you weigh ONE car against another from Pile C. If the first weighing balances, that means the FAKE M is in the last pile. So, all you need is to take ANY car from the final pile, and weigh this against ANY car from ANY of the other piles. If this final weighing balances, the FAKE M is the last car. If it doesn't balance, then, you know you've placed the FAKE M on weighing scale, because you're comparing that to ANY of the other cars (which are REAL Ms)
Scenario (a) means minimum 3 weighings.
The rest of the scenarios are just permutations of the 1st, and they all work out to THREE minimum weighings.
Z
zhenlie
Guest
Re: Question for the Forumers
bro wobbles, eh but in scenario (a) if pile a and b dont balance then need to weigh again with pile c which will take more than 3 weighings right? can enlighten how to get 3 weighing for all scenario?
bro wobbles, eh but in scenario (a) if pile a and b dont balance then need to weigh again with pile c which will take more than 3 weighings right? can enlighten how to get 3 weighing for all scenario?
OptimusWKY
Well-Known Member
wobbles;840295 said:
Hence, realistically minimum is 4. If A and B don't balance, means pile C consists only of real M3. Take pile A and further into two group of 2. If balance, means fake M3 is in pile B. The remaining two steps follow what you have explained, compare one with a genuine one from pile C.
wobbles
Well-Known Member
Re: Question for the Forumers
OK, scenario (b). Again, you divide into 3 piles of 4 cars each. You weigh 1 pile of 4 cars against another pile of 4 cars. The scales do NOT BALANCE. Let's say the LEFT "pan" of the scale is higher than the right side. This either means that the fake M3 is lighter & on the left pan, or the fake M3 is heavier and on the right pan of the scale.
Here's where the fun begins. You MUST remember that the 3rd pile of M3s are now all REAL M3s. These will act as control weight units for what will happen next.
From the weighing scale, move THREE cars from the LEFT pan of the scale over to the other right pan while simultaneously removing 3 cars from that same right pan. Now, replace 3 cars from your CONTROL pile onto the LEFT pan.
Here, you can have the following scenarios:
1. The scale is now in PERFECT balance, which means the FAKE M3 is in one of the 3 cars that you removed from the right pan. This also means that the fake M3 was HEAVIER than the real M3s. The final weighing then is to check either 2 of the M3s from the pile you removed earlier against each other. If they balance, the remaining M3 that was not weighed must be the fake M3. If one is heavier than the other, that heavy one is the fake M3.
2. After moving 3 cars from the LEFT pan over to the right pan & putting 3 cars from the control pile onto the LEFT pan, you still find the scale is still not balanced. Let's say now the RIGHT pan is now higher than the left pan. This means we now know the fake M3 is LIGHTER than the real ones, and that it's in one of the 3 cars that you just moved over from the LEFT pan. For the final 3rd weighing, just weigh any of the 2 cars from the right pan against each other. If it balances, the unweighed car is the fake M3. If it's not balanced, the lighter car is the fake M3.
If you make adjustments to the above scenarios, you'll be able to figure out the false M3 every time, regardless whether it's lighter or heavier. And it'll always only require 3 weighings.
Shit. Am I making sense?!?!?!?!?
OK, scenario (b). Again, you divide into 3 piles of 4 cars each. You weigh 1 pile of 4 cars against another pile of 4 cars. The scales do NOT BALANCE. Let's say the LEFT "pan" of the scale is higher than the right side. This either means that the fake M3 is lighter & on the left pan, or the fake M3 is heavier and on the right pan of the scale.
Here's where the fun begins. You MUST remember that the 3rd pile of M3s are now all REAL M3s. These will act as control weight units for what will happen next.
From the weighing scale, move THREE cars from the LEFT pan of the scale over to the other right pan while simultaneously removing 3 cars from that same right pan. Now, replace 3 cars from your CONTROL pile onto the LEFT pan.
Here, you can have the following scenarios:
1. The scale is now in PERFECT balance, which means the FAKE M3 is in one of the 3 cars that you removed from the right pan. This also means that the fake M3 was HEAVIER than the real M3s. The final weighing then is to check either 2 of the M3s from the pile you removed earlier against each other. If they balance, the remaining M3 that was not weighed must be the fake M3. If one is heavier than the other, that heavy one is the fake M3.
2. After moving 3 cars from the LEFT pan over to the right pan & putting 3 cars from the control pile onto the LEFT pan, you still find the scale is still not balanced. Let's say now the RIGHT pan is now higher than the left pan. This means we now know the fake M3 is LIGHTER than the real ones, and that it's in one of the 3 cars that you just moved over from the LEFT pan. For the final 3rd weighing, just weigh any of the 2 cars from the right pan against each other. If it balances, the unweighed car is the fake M3. If it's not balanced, the lighter car is the fake M3.
If you make adjustments to the above scenarios, you'll be able to figure out the false M3 every time, regardless whether it's lighter or heavier. And it'll always only require 3 weighings.
Shit. Am I making sense?!?!?!?!?
Re: Question for the Forumers
My answer: 12 times
Divide the cars into 4 groups of 3 cars. In the groups of 3 cars, weight against themselves ie. car 1 vs car 2, car 2 vs car 3, car 3 vs car 1
In the groups of all real M3, the scale should balance once another. In the group of the fake M3, the one which is heavier or lighter than the 2 other cars, is the fake one.
My answer: 12 times
Divide the cars into 4 groups of 3 cars. In the groups of 3 cars, weight against themselves ie. car 1 vs car 2, car 2 vs car 3, car 3 vs car 1
In the groups of all real M3, the scale should balance once another. In the group of the fake M3, the one which is heavier or lighter than the 2 other cars, is the fake one.
Re: Question for the Forumers
My answer is 5 times.
Divide the 12 cars into group A, B and C with equal number of cars in it. Using 2 weighing attempts, we find out if the fake is heavier or lighter than the rest. If the fake M3 is in group A and is heavier (or lighter if you prefer), we know for a fact that the fake M3 is heavier (or lighter, same theory).
Weigh car 1 and 2, 3 and 4 (weigh number 4). Get the heavier (or lighter depending on your preference) group and weigh the 2 cars against the real cars taken from group B or C (weigh 5 and 6). The heavier (or lighter if you prefer) car is the fake.
But Kenntona just confirmed I'm wrong...
My answer is 5 times.
Divide the 12 cars into group A, B and C with equal number of cars in it. Using 2 weighing attempts, we find out if the fake is heavier or lighter than the rest. If the fake M3 is in group A and is heavier (or lighter if you prefer), we know for a fact that the fake M3 is heavier (or lighter, same theory).
Weigh car 1 and 2, 3 and 4 (weigh number 4). Get the heavier (or lighter depending on your preference) group and weigh the 2 cars against the real cars taken from group B or C (weigh 5 and 6). The heavier (or lighter if you prefer) car is the fake.
But Kenntona just confirmed I'm wrong...
Last edited by a moderator:
Z
zhenlie
Guest
Re: Question for the Forumers
this is one quality threads... teaches you to identify if your m3 is fake or real... and find out the lawya who loves sausages goes sar lau...
this is one quality threads... teaches you to identify if your m3 is fake or real... and find out the lawya who loves sausages goes sar lau...
Re: Question for the Forumers
Mine is in the bin. I couldn't sleep last night so i gave up after having it at5-6 attempts...
wobbles;840571 said:
Mine is in the bin. I couldn't sleep last night so i gave up after having it at5-6 attempts...
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